Optimal. Leaf size=212 \[ \frac {b \csc ^5(c+d x)}{5 a^2 d}+\frac {b^2 \left (a^2-b^2\right )^2 \log (\sin (c+d x))}{a^7 d}-\frac {b^2 \left (a^2-b^2\right )^2 \log (a+b \sin (c+d x))}{a^7 d}+\frac {b \left (a^2-b^2\right )^2 \csc (c+d x)}{a^6 d}-\frac {\left (a^2-b^2\right )^2 \csc ^2(c+d x)}{2 a^5 d}-\frac {b \left (2 a^2-b^2\right ) \csc ^3(c+d x)}{3 a^4 d}+\frac {\left (2 a^2-b^2\right ) \csc ^4(c+d x)}{4 a^3 d}-\frac {\csc ^6(c+d x)}{6 a d} \]
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Rubi [A] time = 0.24, antiderivative size = 212, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 29, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.103, Rules used = {2837, 12, 894} \[ \frac {\left (2 a^2-b^2\right ) \csc ^4(c+d x)}{4 a^3 d}-\frac {b \left (2 a^2-b^2\right ) \csc ^3(c+d x)}{3 a^4 d}-\frac {\left (a^2-b^2\right )^2 \csc ^2(c+d x)}{2 a^5 d}+\frac {b \left (a^2-b^2\right )^2 \csc (c+d x)}{a^6 d}+\frac {b^2 \left (a^2-b^2\right )^2 \log (\sin (c+d x))}{a^7 d}-\frac {b^2 \left (a^2-b^2\right )^2 \log (a+b \sin (c+d x))}{a^7 d}+\frac {b \csc ^5(c+d x)}{5 a^2 d}-\frac {\csc ^6(c+d x)}{6 a d} \]
Antiderivative was successfully verified.
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Rule 12
Rule 894
Rule 2837
Rubi steps
\begin {align*} \int \frac {\cot ^5(c+d x) \csc ^2(c+d x)}{a+b \sin (c+d x)} \, dx &=\frac {\operatorname {Subst}\left (\int \frac {b^7 \left (b^2-x^2\right )^2}{x^7 (a+x)} \, dx,x,b \sin (c+d x)\right )}{b^5 d}\\ &=\frac {b^2 \operatorname {Subst}\left (\int \frac {\left (b^2-x^2\right )^2}{x^7 (a+x)} \, dx,x,b \sin (c+d x)\right )}{d}\\ &=\frac {b^2 \operatorname {Subst}\left (\int \left (\frac {b^4}{a x^7}-\frac {b^4}{a^2 x^6}+\frac {-2 a^2 b^2+b^4}{a^3 x^5}+\frac {2 a^2 b^2-b^4}{a^4 x^4}+\frac {\left (a^2-b^2\right )^2}{a^5 x^3}-\frac {\left (a^2-b^2\right )^2}{a^6 x^2}+\frac {\left (a^2-b^2\right )^2}{a^7 x}-\frac {\left (a^2-b^2\right )^2}{a^7 (a+x)}\right ) \, dx,x,b \sin (c+d x)\right )}{d}\\ &=\frac {b \left (a^2-b^2\right )^2 \csc (c+d x)}{a^6 d}-\frac {\left (a^2-b^2\right )^2 \csc ^2(c+d x)}{2 a^5 d}-\frac {b \left (2 a^2-b^2\right ) \csc ^3(c+d x)}{3 a^4 d}+\frac {\left (2 a^2-b^2\right ) \csc ^4(c+d x)}{4 a^3 d}+\frac {b \csc ^5(c+d x)}{5 a^2 d}-\frac {\csc ^6(c+d x)}{6 a d}+\frac {b^2 \left (a^2-b^2\right )^2 \log (\sin (c+d x))}{a^7 d}-\frac {b^2 \left (a^2-b^2\right )^2 \log (a+b \sin (c+d x))}{a^7 d}\\ \end {align*}
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Mathematica [A] time = 2.86, size = 165, normalized size = 0.78 \[ \frac {-10 a^6 \csc ^6(c+d x)+12 a^5 b \csc ^5(c+d x)+60 \left (b^3-a^2 b\right )^2 (\log (\sin (c+d x))-\log (a+b \sin (c+d x)))-30 a^2 \left (a^2-b^2\right )^2 \csc ^2(c+d x)+60 a b \left (a^2-b^2\right )^2 \csc (c+d x)+15 a^4 \left (2 a^2-b^2\right ) \csc ^4(c+d x)+20 a^3 b \left (b^2-2 a^2\right ) \csc ^3(c+d x)}{60 a^7 d} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.74, size = 464, normalized size = 2.19 \[ \frac {10 \, a^{6} - 45 \, a^{4} b^{2} + 30 \, a^{2} b^{4} + 30 \, {\left (a^{6} - 2 \, a^{4} b^{2} + a^{2} b^{4}\right )} \cos \left (d x + c\right )^{4} - 15 \, {\left (2 \, a^{6} - 7 \, a^{4} b^{2} + 4 \, a^{2} b^{4}\right )} \cos \left (d x + c\right )^{2} - 60 \, {\left ({\left (a^{4} b^{2} - 2 \, a^{2} b^{4} + b^{6}\right )} \cos \left (d x + c\right )^{6} - a^{4} b^{2} + 2 \, a^{2} b^{4} - b^{6} - 3 \, {\left (a^{4} b^{2} - 2 \, a^{2} b^{4} + b^{6}\right )} \cos \left (d x + c\right )^{4} + 3 \, {\left (a^{4} b^{2} - 2 \, a^{2} b^{4} + b^{6}\right )} \cos \left (d x + c\right )^{2}\right )} \log \left (b \sin \left (d x + c\right ) + a\right ) + 60 \, {\left ({\left (a^{4} b^{2} - 2 \, a^{2} b^{4} + b^{6}\right )} \cos \left (d x + c\right )^{6} - a^{4} b^{2} + 2 \, a^{2} b^{4} - b^{6} - 3 \, {\left (a^{4} b^{2} - 2 \, a^{2} b^{4} + b^{6}\right )} \cos \left (d x + c\right )^{4} + 3 \, {\left (a^{4} b^{2} - 2 \, a^{2} b^{4} + b^{6}\right )} \cos \left (d x + c\right )^{2}\right )} \log \left (-\frac {1}{2} \, \sin \left (d x + c\right )\right ) - 4 \, {\left (8 \, a^{5} b - 25 \, a^{3} b^{3} + 15 \, a b^{5} + 15 \, {\left (a^{5} b - 2 \, a^{3} b^{3} + a b^{5}\right )} \cos \left (d x + c\right )^{4} - 5 \, {\left (4 \, a^{5} b - 11 \, a^{3} b^{3} + 6 \, a b^{5}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )}{60 \, {\left (a^{7} d \cos \left (d x + c\right )^{6} - 3 \, a^{7} d \cos \left (d x + c\right )^{4} + 3 \, a^{7} d \cos \left (d x + c\right )^{2} - a^{7} d\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.23, size = 301, normalized size = 1.42 \[ \frac {\frac {60 \, {\left (a^{4} b^{2} - 2 \, a^{2} b^{4} + b^{6}\right )} \log \left ({\left | \sin \left (d x + c\right ) \right |}\right )}{a^{7}} - \frac {60 \, {\left (a^{4} b^{3} - 2 \, a^{2} b^{5} + b^{7}\right )} \log \left ({\left | b \sin \left (d x + c\right ) + a \right |}\right )}{a^{7} b} - \frac {147 \, a^{4} b^{2} \sin \left (d x + c\right )^{6} - 294 \, a^{2} b^{4} \sin \left (d x + c\right )^{6} + 147 \, b^{6} \sin \left (d x + c\right )^{6} - 60 \, a^{5} b \sin \left (d x + c\right )^{5} + 120 \, a^{3} b^{3} \sin \left (d x + c\right )^{5} - 60 \, a b^{5} \sin \left (d x + c\right )^{5} + 30 \, a^{6} \sin \left (d x + c\right )^{4} - 60 \, a^{4} b^{2} \sin \left (d x + c\right )^{4} + 30 \, a^{2} b^{4} \sin \left (d x + c\right )^{4} + 40 \, a^{5} b \sin \left (d x + c\right )^{3} - 20 \, a^{3} b^{3} \sin \left (d x + c\right )^{3} - 30 \, a^{6} \sin \left (d x + c\right )^{2} + 15 \, a^{4} b^{2} \sin \left (d x + c\right )^{2} - 12 \, a^{5} b \sin \left (d x + c\right ) + 10 \, a^{6}}{a^{7} \sin \left (d x + c\right )^{6}}}{60 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.55, size = 330, normalized size = 1.56 \[ -\frac {b^{2} \ln \left (a +b \sin \left (d x +c \right )\right )}{a^{3} d}+\frac {2 \ln \left (a +b \sin \left (d x +c \right )\right ) b^{4}}{d \,a^{5}}-\frac {b^{6} \ln \left (a +b \sin \left (d x +c \right )\right )}{d \,a^{7}}-\frac {1}{6 d a \sin \left (d x +c \right )^{6}}+\frac {1}{2 d a \sin \left (d x +c \right )^{4}}-\frac {b^{2}}{4 d \,a^{3} \sin \left (d x +c \right )^{4}}-\frac {1}{2 d a \sin \left (d x +c \right )^{2}}+\frac {b^{2}}{d \,a^{3} \sin \left (d x +c \right )^{2}}-\frac {b^{4}}{2 d \,a^{5} \sin \left (d x +c \right )^{2}}-\frac {2 b}{3 d \,a^{2} \sin \left (d x +c \right )^{3}}+\frac {b^{3}}{3 d \,a^{4} \sin \left (d x +c \right )^{3}}+\frac {b^{2} \ln \left (\sin \left (d x +c \right )\right )}{a^{3} d}-\frac {2 \ln \left (\sin \left (d x +c \right )\right ) b^{4}}{d \,a^{5}}+\frac {b^{6} \ln \left (\sin \left (d x +c \right )\right )}{d \,a^{7}}+\frac {b}{5 d \,a^{2} \sin \left (d x +c \right )^{5}}+\frac {b}{d \,a^{2} \sin \left (d x +c \right )}-\frac {2 b^{3}}{d \,a^{4} \sin \left (d x +c \right )}+\frac {b^{5}}{d \,a^{6} \sin \left (d x +c \right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.32, size = 206, normalized size = 0.97 \[ -\frac {\frac {60 \, {\left (a^{4} b^{2} - 2 \, a^{2} b^{4} + b^{6}\right )} \log \left (b \sin \left (d x + c\right ) + a\right )}{a^{7}} - \frac {60 \, {\left (a^{4} b^{2} - 2 \, a^{2} b^{4} + b^{6}\right )} \log \left (\sin \left (d x + c\right )\right )}{a^{7}} - \frac {12 \, a^{4} b \sin \left (d x + c\right ) + 60 \, {\left (a^{4} b - 2 \, a^{2} b^{3} + b^{5}\right )} \sin \left (d x + c\right )^{5} - 10 \, a^{5} - 30 \, {\left (a^{5} - 2 \, a^{3} b^{2} + a b^{4}\right )} \sin \left (d x + c\right )^{4} - 20 \, {\left (2 \, a^{4} b - a^{2} b^{3}\right )} \sin \left (d x + c\right )^{3} + 15 \, {\left (2 \, a^{5} - a^{3} b^{2}\right )} \sin \left (d x + c\right )^{2}}{a^{6} \sin \left (d x + c\right )^{6}}}{60 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 12.31, size = 514, normalized size = 2.42 \[ \frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,\left (\frac {1}{64\,a}-\frac {b^2}{64\,a^3}\right )}{d}-\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3\,\left (\frac {b}{96\,a^2}+\frac {2\,b\,\left (\frac {1}{16\,a}-\frac {b^2}{16\,a^3}\right )}{3\,a}\right )}{d}-\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6}{384\,a\,d}+\frac {\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (\frac {b}{32\,a^2}-\frac {2\,b\,\left (\frac {b^2}{16\,a^3}-\frac {5}{64\,a}+\frac {2\,b\,\left (\frac {b}{32\,a^2}+\frac {2\,b\,\left (\frac {1}{16\,a}-\frac {b^2}{16\,a^3}\right )}{a}\right )}{a}\right )}{a}+\frac {2\,b\,\left (\frac {1}{16\,a}-\frac {b^2}{16\,a^3}\right )}{a}\right )}{d}+\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,\left (\frac {b^2}{32\,a^3}-\frac {5}{128\,a}+\frac {b\,\left (\frac {b}{32\,a^2}+\frac {2\,b\,\left (\frac {1}{16\,a}-\frac {b^2}{16\,a^3}\right )}{a}\right )}{a}\right )}{d}+\frac {\ln \left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )\,\left (a^4\,b^2-2\,a^2\,b^4+b^6\right )}{a^7\,d}+\frac {b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5}{160\,a^2\,d}-\frac {\ln \left (a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+2\,b\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )+a\right )\,\left (a^4\,b^2-2\,a^2\,b^4+b^6\right )}{a^7\,d}-\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3\,\left (\frac {10\,a^4\,b}{3}-\frac {8\,a^2\,b^3}{3}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,\left (\frac {5\,a^5}{2}-12\,a^3\,b^2+8\,a\,b^4\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5\,\left (20\,a^4\,b-56\,a^2\,b^3+32\,b^5\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,\left (a^5-a^3\,b^2\right )+\frac {a^5}{6}-\frac {2\,a^4\,b\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{5}}{64\,a^6\,d\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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